Solved 2024/02 P1 + P2
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2024/02/2.md
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## \-\-- Day 2: Red-Nosed Reports \-\--
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Fortunately, the first location The Historians want to search isn\'t a
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long walk from the Chief Historian\'s office.
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While the [Red-Nosed Reindeer nuclear fusion/fission
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plant](/2015/day/19) appears to contain no sign of the Chief Historian,
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the engineers there run up to you as soon as they see you. Apparently,
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they *still* talk about the time Rudolph was saved through molecular
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synthesis from a single electron.
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They\'re quick to add that - since you\'re already here - they\'d really
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appreciate your help analyzing some unusual data from the Red-Nosed
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reactor. You turn to check if The Historians are waiting for you, but
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they seem to have already divided into groups that are currently
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searching every corner of the facility. You offer to help with the
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unusual data.
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The unusual data (your puzzle input) consists of many *reports*, one
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report per line. Each report is a list of numbers called *levels* that
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are separated by spaces. For example:
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7 6 4 2 1
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1 2 7 8 9
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9 7 6 2 1
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1 3 2 4 5
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8 6 4 4 1
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1 3 6 7 9
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This example data contains six reports each containing five levels.
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The engineers are trying to figure out which reports are *safe*. The
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Red-Nosed reactor safety systems can only tolerate levels that are
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either gradually increasing or gradually decreasing. So, a report only
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counts as safe if both of the following are true:
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- The levels are either *all increasing* or *all decreasing*.
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- Any two adjacent levels differ by *at least one* and *at most
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three*.
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In the example above, the reports can be found safe or unsafe by
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checking those rules:
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- `7 6 4 2 1`: *Safe* because the levels are all decreasing by 1 or 2.
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- `1 2 7 8 9`: *Unsafe* because `2 7` is an increase of 5.
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- `9 7 6 2 1`: *Unsafe* because `6 2` is a decrease of 4.
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- `1 3 2 4 5`: *Unsafe* because `1 3` is increasing but `3 2` is
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decreasing.
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- `8 6 4 4 1`: *Unsafe* because `4 4` is neither an increase or a
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decrease.
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- `1 3 6 7 9`: *Safe* because the levels are all increasing by 1, 2,
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or 3.
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So, in this example, `2` reports are *safe*.
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Analyze the unusual data from the engineers. *How many reports are
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safe?*
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Your puzzle answer was `252`.
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## \-\-- Part Two \-\-- {#part2}
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The engineers are surprised by the low number of safe reports until they
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realize they forgot to tell you about the [Problem
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Dampener]{title="I need to get one of these!"}.
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The Problem Dampener is a reactor-mounted module that lets the reactor
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safety systems *tolerate a single bad level* in what would otherwise be
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a safe report. It\'s like the bad level never happened!
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Now, the same rules apply as before, except if removing a single level
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from an unsafe report would make it safe, the report instead counts as
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safe.
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More of the above example\'s reports are now safe:
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- `7 6 4 2 1`: *Safe* without removing any level.
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- `1 2 7 8 9`: *Unsafe* regardless of which level is removed.
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- `9 7 6 2 1`: *Unsafe* regardless of which level is removed.
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- `1 3 2 4 5`: *Safe* by removing the second level, `3`.
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- `8 6 4 4 1`: *Safe* by removing the third level, `4`.
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- `1 3 6 7 9`: *Safe* without removing any level.
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Thanks to the Problem Dampener, `4` reports are actually *safe*!
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Update your analysis by handling situations where the Problem Dampener
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can remove a single level from unsafe reports. *How many reports are now
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safe?*
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Your puzzle answer was `324`.
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Both parts of this puzzle are complete! They provide two gold stars:
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\*\*
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At this point, you should [return to your Advent calendar](/2024) and
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try another puzzle.
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If you still want to see it, you can [get your puzzle
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input](2/input).
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2024/02/solution.py
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2024/02/solution.py
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#!/bin/python3
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import sys,re
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from pprint import pprint
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sys.path.insert(0, '../../')
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from fred import list2int,get_re,nprint,lprint
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input_f = 'input'
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part = 2
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#########################################
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# #
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# Part 1 #
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# #
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#########################################
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def checkInc(line:list):
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safe = False
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for i in range(0,len(line)-1):
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if line[i] < line[i+1]:
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safe = True
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else:
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return False
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return safe
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def checkDesc(line:list):
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safe = False
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for i in range(0,len(line)-1):
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if line[i] > line[i+1]:
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safe = True
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else:
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return False
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return safe
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def checkJump(line:list):
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safe = False
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for i in range(0,len(line)-1):
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if abs(line[i] - line[i+1]) in [1,2,3]:
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safe = True
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else:
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return False
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return safe
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if part == 1:
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reports = []
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count = 0
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with open(input_f) as file:
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for line in file:
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reports.append(list2int(line.rstrip().split()))
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for r in reports:
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if (checkDesc(r) or checkInc(r)) and checkJump(r):
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count += 1
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print(count)
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#########################################
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# #
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# Part 2 #
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# #
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#########################################
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if part == 2:
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reports = []
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count = 0
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j = 0
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with open(input_f) as file:
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for line in file:
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reports.append(list2int(line.rstrip().split()))
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for rdx,r in enumerate(reports):
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if (checkDesc(r) or checkInc(r)) and checkJump(r):
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count += 1
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else:
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secondSafe = False
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while not secondSafe:
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tmp = r[:j] + r[j + 1:]
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if (checkDesc(tmp) or checkInc(tmp)) and checkJump(tmp):
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count += 1
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secondSafe = True
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if not secondSafe and j > len(tmp)-1:
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break
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j += 1
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j = 0
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secondSafe = False
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print(count)
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1
2024/02/test2
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1
2024/02/test2
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8 6 4 4 1
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2
2024/02/test3
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2
2024/02/test3
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1 1 2
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2 6 1
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## 2024
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.--'~ ~ ~| .-' * \ / '-. 1 **
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.--'~ ,* ~ | | <o> \_\_\|_/__/ | 2 **
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## 2023
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. * ~~~~ /\ ' . 14
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.-----------------------------------------------.
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| o──────*──────┐o┬──────────────────┐┌───────┐ | 25 *
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| o──*──┐└───┐o─┴─┘o────────┬─────o┌─┘├───o┌──┤ | 24 *
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| o──*──┐└───┐o─┴─┘o────────┬─────o┌─┘├───o┌──┤ | 24 **
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| ┌──┘o─┴────┘┌────────────*├──────┘o─┘┌───┘┌─┘ | 23 *
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| ├───┐┌──────┴o*──|(────┐┌┘└──────────┘o┬──┘o┐ | 22 **
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| └┐o┐└┘*───────┘o┬─┬──┬┴┴┴┬───┬┴┴┴┴┬───┐└────┤ | 21 **
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