Solved 2024/02 P1 + P2

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FrederikBaerentsen 2024-12-02 09:54:52 +01:00
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## \-\-- Day 2: Red-Nosed Reports \-\--
Fortunately, the first location The Historians want to search isn\'t a
long walk from the Chief Historian\'s office.
While the [Red-Nosed Reindeer nuclear fusion/fission
plant](/2015/day/19) appears to contain no sign of the Chief Historian,
the engineers there run up to you as soon as they see you. Apparently,
they *still* talk about the time Rudolph was saved through molecular
synthesis from a single electron.
They\'re quick to add that - since you\'re already here - they\'d really
appreciate your help analyzing some unusual data from the Red-Nosed
reactor. You turn to check if The Historians are waiting for you, but
they seem to have already divided into groups that are currently
searching every corner of the facility. You offer to help with the
unusual data.
The unusual data (your puzzle input) consists of many *reports*, one
report per line. Each report is a list of numbers called *levels* that
are separated by spaces. For example:
7 6 4 2 1
1 2 7 8 9
9 7 6 2 1
1 3 2 4 5
8 6 4 4 1
1 3 6 7 9
This example data contains six reports each containing five levels.
The engineers are trying to figure out which reports are *safe*. The
Red-Nosed reactor safety systems can only tolerate levels that are
either gradually increasing or gradually decreasing. So, a report only
counts as safe if both of the following are true:
- The levels are either *all increasing* or *all decreasing*.
- Any two adjacent levels differ by *at least one* and *at most
three*.
In the example above, the reports can be found safe or unsafe by
checking those rules:
- `7 6 4 2 1`: *Safe* because the levels are all decreasing by 1 or 2.
- `1 2 7 8 9`: *Unsafe* because `2 7` is an increase of 5.
- `9 7 6 2 1`: *Unsafe* because `6 2` is a decrease of 4.
- `1 3 2 4 5`: *Unsafe* because `1 3` is increasing but `3 2` is
decreasing.
- `8 6 4 4 1`: *Unsafe* because `4 4` is neither an increase or a
decrease.
- `1 3 6 7 9`: *Safe* because the levels are all increasing by 1, 2,
or 3.
So, in this example, `2` reports are *safe*.
Analyze the unusual data from the engineers. *How many reports are
safe?*
Your puzzle answer was `252`.
## \-\-- Part Two \-\-- {#part2}
The engineers are surprised by the low number of safe reports until they
realize they forgot to tell you about the [Problem
Dampener]{title="I need to get one of these!"}.
The Problem Dampener is a reactor-mounted module that lets the reactor
safety systems *tolerate a single bad level* in what would otherwise be
a safe report. It\'s like the bad level never happened!
Now, the same rules apply as before, except if removing a single level
from an unsafe report would make it safe, the report instead counts as
safe.
More of the above example\'s reports are now safe:
- `7 6 4 2 1`: *Safe* without removing any level.
- `1 2 7 8 9`: *Unsafe* regardless of which level is removed.
- `9 7 6 2 1`: *Unsafe* regardless of which level is removed.
- `1 3 2 4 5`: *Safe* by removing the second level, `3`.
- `8 6 4 4 1`: *Safe* by removing the third level, `4`.
- `1 3 6 7 9`: *Safe* without removing any level.
Thanks to the Problem Dampener, `4` reports are actually *safe*!
Update your analysis by handling situations where the Problem Dampener
can remove a single level from unsafe reports. *How many reports are now
safe?*
Your puzzle answer was `324`.
Both parts of this puzzle are complete! They provide two gold stars:
\*\*
At this point, you should [return to your Advent calendar](/2024) and
try another puzzle.
If you still want to see it, you can [get your puzzle
input](2/input).

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#!/bin/python3
import sys,re
from pprint import pprint
sys.path.insert(0, '../../')
from fred import list2int,get_re,nprint,lprint
input_f = 'input'
part = 2
#########################################
# #
# Part 1 #
# #
#########################################
def checkInc(line:list):
safe = False
for i in range(0,len(line)-1):
if line[i] < line[i+1]:
safe = True
else:
return False
return safe
def checkDesc(line:list):
safe = False
for i in range(0,len(line)-1):
if line[i] > line[i+1]:
safe = True
else:
return False
return safe
def checkJump(line:list):
safe = False
for i in range(0,len(line)-1):
if abs(line[i] - line[i+1]) in [1,2,3]:
safe = True
else:
return False
return safe
if part == 1:
reports = []
count = 0
with open(input_f) as file:
for line in file:
reports.append(list2int(line.rstrip().split()))
for r in reports:
if (checkDesc(r) or checkInc(r)) and checkJump(r):
count += 1
print(count)
#########################################
# #
# Part 2 #
# #
#########################################
if part == 2:
reports = []
count = 0
j = 0
with open(input_f) as file:
for line in file:
reports.append(list2int(line.rstrip().split()))
for rdx,r in enumerate(reports):
if (checkDesc(r) or checkInc(r)) and checkJump(r):
count += 1
else:
secondSafe = False
while not secondSafe:
tmp = r[:j] + r[j + 1:]
if (checkDesc(tmp) or checkInc(tmp)) and checkJump(tmp):
count += 1
secondSafe = True
if not secondSafe and j > len(tmp)-1:
break
j += 1
j = 0
secondSafe = False
print(count)

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8 6 4 4 1

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1 1 2
2 6 1

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## 2024
.--'~ ~ ~| .-' * \ / '-. 1 **
.--'~ ,* ~ | | <o> \_\_\|_/__/ | 2 **
## 2023
. * ~~~~ /\ ' . 14
@ -62,7 +62,7 @@
.-----------------------------------------------.
| o──────*──────┐o┬──────────────────┐┌───────┐ | 25 *
| o──*──┐└───┐o─┴─┘o────────┬─────o┌─┘├───o┌──┤ | 24 *
| o──*──┐└───┐o─┴─┘o────────┬─────o┌─┘├───o┌──┤ | 24 **
| ┌──┘o─┴────┘┌────────────*├──────┘o─┘┌───┘┌─┘ | 23 *
| ├───┐┌──────┴o*──|(────┐┌┘└──────────┘o┬──┘o┐ | 22 **
| └┐o┐└┘*───────┘o┬─┬──┬┴┴┴┬───┬┴┴┴┴┬───┐└────┤ | 21 **