Started 2023-12-07

This commit is contained in:
FrederikBaerentsen 2023-12-07 15:58:07 +01:00
parent ff94e70daa
commit bb1ec64afc
2 changed files with 128 additions and 0 deletions

11
2023/day7/exp Normal file
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@ -0,0 +1,11 @@
32T3K 765
T55J5 684
AA8AA 21
KK677 28
AAAAA 123
KTJJT 220
23332 1
A23A4 64
QQQJA 483
23456 64
HNJIP 317

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@ -3,11 +3,128 @@
import re import re
import sys import sys
from pprint import pprint from pprint import pprint
from collections import Counter
input_f = sys.argv[1] input_f = sys.argv[1]
d =[] d =[]
rank = 0
strength = 'AKQJT98765432'
print(strength)
with open(input_f) as file: with open(input_f) as file:
for line in file: for line in file:
d.append(line.split())
pprint(d)
print()
def same_kind(x):
s = Counter(x)
for i in s.values():
if i == 4:
return True
return False
def five_of_kind(x):
if len(Counter(x)) == 1:
return True
return False
def full_house(x):
#print('full_house')
s = Counter(x)
if len(s) != 2:
return False
else:
tmp = list(s.values())
if (tmp[0] == 2 or tmp[0] == 3) and (tmp[1] == 2 or tmp[1] == 3):
return True
else:
return False
def three_of_kind(x):
s = Counter(x)
for i in s.values():
if i == 3:
return True
return False
def pairs(x):
s = Counter(x)
pairs = 0
for i in s.values():
if i == 2:
pairs += 1
return pairs
for idx,i in enumerate(d):
d[idx].append(rank)
# Five of a kind, where all five cards have the same label: AAAAA
if five_of_kind(d[idx][0]) == True:
d[idx][2] = 7
continue
#Four of a kind, where four cards have the same label and one card has a different label: AA8AA
if same_kind(d[idx][0]) == True:
d[idx][2] = 6
continue
#Full house, where three cards have the same label, and the remaining two cards share a different label: 23332
if full_house(d[idx][0]) == True:
d[idx][2] = 5
continue
#Three of a kind, where three cards have the same label, and the remaining two cards are each different from any other card in the hand: TTT98
if three_of_kind(d[idx][0]) == True:
d[idx][2] = 4
continue
#Two pair, where two cards share one label, two other cards share a second label, and the remaining card has a third label: 23432
if pairs(d[idx][0]) == 2:
d[idx][2] = 3
continue
#One pair, where two cards share one label, and the other three cards have a different label from the pair and each other: A23A4
if pairs(d[idx][0]) == 1:
d[idx][2] = 2
continue
#High card, where all cards' labels are distinct: 23456
if pairs(d[idx][0]) == 0:
d[idx][2] = 1
continue
#d.sort()
d = sorted(d, key=lambda x: x[2])
print()
pprint(d)
print()
for idx,i in enumerate(d):
if idx == len(d)-1:
break
else:
if d[idx][2] == d[idx+1][2]:
#print('Comparing ' + str(d[idx][0]) + ' to ' + str(d[idx+1][0]))
tmp = list(d[idx][0])
tmp2 = list(d[idx+1][0])
for x in range(0,5):
if tmp[x] != tmp2[x]:
#print(tmp[x],tmp2[x])
if strength.find(tmp[x]) < strength.find(tmp2[x]):
d[idx],d[idx+1] = d[idx+1],d[idx]
break
result = 0
for idx,i in enumerate(d):
x = i[1]
result += (int(x) * (idx+1))
pprint(d) pprint(d)
print(result)