Solved 2015/12 P1

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FrederikBaerentsen 2024-12-10 19:49:31 +01:00
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## \-\-- Day 12: JSAbacusFramework.io \-\--
Santa\'s Accounting-Elves need help balancing the books after a recent
order. Unfortunately, their accounting software uses a peculiar storage
format. That\'s where you come in.
They have a [JSON](http://json.org/) document which contains a variety
of things: arrays (`[1,2,3]`), objects (`{"a":1, "b":2}`), numbers, and
strings. Your first job is to simply find all of the *numbers*
throughout the document and add them together.
For example:
- `[1,2,3]` and `{"a":2,"b":4}` both have a sum of `6`.
- `[[[3]]]` and `{"a":{"b":4},"c":-1}` both have a sum of `3`.
- `{"a":[-1,1]}` and `[-1,{"a":1}]` both have a sum of `0`.
- `[]` and `{}` both have a sum of `0`.
You will not
encounter
any strings containing numbers.
What is the *sum of all numbers* in the document?
Your puzzle answer was `191164`.
The first half of this puzzle is complete! It provides one gold star: \*
## \-\-- Part Two \-\-- {#part2}
Uh oh - the Accounting-Elves have realized that they double-counted
everything *red*.
Ignore any object (and all of its children) which has any property with
the value `"red"`. Do this only for objects (`{...}`), not arrays
(`[...]`).
- `[1,2,3]` still has a sum of `6`.
- `[1,{"c":"red","b":2},3]` now has a sum of `4`, because the middle
object is ignored.
- `{"d":"red","e":[1,2,3,4],"f":5}` now has a sum of `0`, because the
entire structure is ignored.
- `[1,"red",5]` has a sum of `6`, because `"red"` in an array has no
effect.
Answer:
Although it hasn\'t changed, you can still [get your puzzle
input](12/input).

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#!/bin/python3
import sys,time,re
from pprint import pprint
sys.path.insert(0, '../../')
from fred import list2int,get_re,nprint,lprint,loadFile
start_time = time.time()
input_f = 'input'
part = 1
#########################################
# #
# Part 1 #
# #
#########################################
if part == 1:
with open(input_f) as file:
instructions = file.readline().rstrip()
match = re.findall(r"(-?\d+)",instructions)
print(sum(list2int(match)))
#########################################
# #
# Part 2 #
# #
#########################################
if part == 2:
exit()
print("--- %s seconds ---" % (time.time() - start_time))