Aded 2017/09 part 1
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2017/09/9.md
26
2017/09/9.md
@ -70,6 +70,30 @@ group that immediately contains it. (The outermost group gets a score of
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*What is the total score* for all groups in your input?
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To begin, [get your puzzle input](9/input).
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Your puzzle answer was `11898`.
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The first half of this puzzle is complete! It provides one gold star: \*
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## \-\-- Part Two \-\-- {#part2}
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Now, you\'re ready to remove the garbage.
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To prove you\'ve removed it, you need to count all of the characters
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within the garbage. The leading and trailing `<` and `>` don\'t count,
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nor do any canceled characters or the `!` doing the canceling.
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- `<>`, `0` characters.
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- `<random characters>`, `17` characters.
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- `<<<<>`, `3` characters.
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- `<{!>}>`, `2` characters.
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- `<!!>`, `0` characters.
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- `<!!!>>`, `0` characters.
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- `<{o"i!a,<{i<a>`, `10` characters.
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*How many non-canceled characters are within the garbage* in your puzzle
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input?
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Answer:
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Although it hasn\'t changed, you can still [get your puzzle
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input](9/input).
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@ -2,48 +2,31 @@
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import sys,re
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from pprint import pprint
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input_f = 'test'
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input_f = 'input'
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part = 1
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part = -1
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#########################################
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# #
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# Part 1 #
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# #
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#########################################
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if part == 1:
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with open(input_f) as file:
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for line in file:
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print(line.rstrip())
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clean_string = re.sub(r"!.", "", line.rstrip())
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clean_string = re.sub(r"<.*?>", "", clean_string)
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clean_string = re.sub(r",", "", clean_string)
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#print(clean_string)
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level = 0
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numbers = []
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for i in clean_string:
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if i == '{':
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level += 1
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if i == '}':
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numbers.append(level)
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level -= 1
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count = 1
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score = 0
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iteration = 0
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#print('Score of ',end='')
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while True:
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#print('Iteration: ', iteration)
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matches = re.findall(r"\{\}", clean_string)
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if not matches:
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#print(increment,end='')
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print('=',score)
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break
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print(sum(numbers))
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clean_string = re.sub(r"\{\}", "", clean_string)
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iteration += 1
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for x in range(0,len(matches)):
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score += iteration
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print(iteration,end="")
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#print(clean_string)
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#rint(count)
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input()
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#########################################
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# #
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# Part 2 #
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