Solved 2024/04 P1 + P2

2024/03/notes.txt

@@ -0,0 +1,17 @@
+    # # Second attempt
+
+    # instructions = ""
+
+    # with open(input_f) as file:
+    #     for line in file:
+    #         instructions += line
+    # print(instructions)
+
+
+# #(do\(\).*?mul\((\d+),{1}(\d+)\))
+
+
+
+# (?<=do\(\))([^d]*(mul\(\d+,\d+\))[^d]*)+(?=don't\(\))
+ 
+# (?<=do\(\))[^m]*(mul\((\d+),{1}(\d+)\)*)*[^d]*(?=don't\(\))

2024/03/solution.py

@@ -43,9 +43,6 @@ if part == 2:
                     if do:
                         m = get_re(r"mul\((\d+),{1}(\d+)\)",match)
                         result += (int(m.group(1))*int(m.group(2)))
-print(result)
-
+    print(result)
 # Not really happy with my code. I would prefer to find all mul(x,y) between do() and don't(), 
-# instead of finding all the mul/do/don't and then turning calculation on/off. 
-
-#(do\(\).*?mul\((\d+),{1}(\d+)\))
+# instead of finding all the mul/do/don't and then turning calculation on/off. 

2024/03/test.py

@@ -1,16 +0,0 @@
-from re import findall
-
-total1 = total2 = 0
-enabled = True
-data = open('input').read()
-
-for a, b, do, dont in findall(r"mul\((\d+),(\d+)\)|(do\(\))|(don't\(\))", data):
-    if do or dont:
-        enabled = bool(do)
-    else:
-        x = int(a) * int(b)
-        total1 += x
-        total2 += x * enabled
-
-print(total1, total2)
-