Solved 2024/13 P2

This commit is contained in:
FrederikBaerentsen 2024-12-13 21:45:55 +01:00
parent 2926202888
commit 486144352b
2 changed files with 47 additions and 13 deletions

View File

@ -83,8 +83,6 @@ tokens you would have to spend to win all possible prizes?*
Your puzzle answer was `30973`. Your puzzle answer was `30973`.
The first half of this puzzle is complete! It provides one gold star: \*
## \-\-- Part Two \-\-- {#part2} ## \-\-- Part Two \-\-- {#part2}
As you go to win the first prize, you discover that the claw is nowhere As you go to win the first prize, you discover that the claw is nowhere
@ -119,8 +117,14 @@ Using the corrected prize coordinates, figure out how to win as many
prizes as possible. *What is the fewest tokens you would have to spend prizes as possible. *What is the fewest tokens you would have to spend
to win all possible prizes?* to win all possible prizes?*
Answer: Your puzzle answer was `95688837203288`.
Although it hasn\'t changed, you can still [get your puzzle Both parts of this puzzle are complete! They provide two gold stars:
\*\*
At this point, you should [return to your Advent calendar](/2024) and
try another puzzle.
If you still want to see it, you can [get your puzzle
input](13/input). input](13/input).

View File

@ -14,7 +14,6 @@ input_f = 'input'
# # # #
######################################### #########################################
def part1(): def part1():
instructions = [] instructions = []
with open(input_f) as file: with open(input_f) as file:
@ -23,7 +22,6 @@ def part1():
if match: if match:
instructions.append(list2int([match.group(1),match.group(2)])) instructions.append(list2int([match.group(1),match.group(2)]))
#print(instructions)
a_cost = 3 a_cost = 3
b_cost = 1 b_cost = 1
@ -34,7 +32,6 @@ def part1():
result = 0 result = 0
for idx, inst in enumerate(instructions): for idx, inst in enumerate(instructions):
#print(inst)
if idx%3 == 0: if idx%3 == 0:
a = (inst[0],inst[1]) a = (inst[0],inst[1])
@ -46,15 +43,13 @@ def part1():
eq2 = Eq(a[1]*x + b[1]*y,r[1]) eq2 = Eq(a[1]*x + b[1]*y,r[1])
s = solve((eq1,eq2),(x,y)) s = solve((eq1,eq2),(x,y))
#print(s)
if s: if s:
result += s[x]*a_cost result += s[x]*a_cost
result += s[y]*b_cost result += s[y]*b_cost
#input()
return result return result
start_time = time.time() start_time = time.time()
print('Part 1:',part1(), '\t\t', round((time.time() - start_time)*1000), 'ms') #rint('Part 1:',part1(), '\t\t', round((time.time() - start_time)*1000), 'ms')
######################################### #########################################
@ -62,8 +57,43 @@ print('Part 1:',part1(), '\t\t', round((time.time() - start_time)*1000), 'ms')
# Part 2 # # Part 2 #
# # # #
######################################### #########################################
def part1(): def part2():
return instructions = []
with open(input_f) as file:
for line in file:
match = get_re(r".*X[\+|=](\d+), Y[\+|=](\d+)",line.rstrip())
if match:
instructions.append(list2int([match.group(1),match.group(2)]))
a_cost = 3
b_cost = 1
a = ()
b = ()
r = ()
x,y = symbols('x y',integer=True)
result = 0
for idx, inst in enumerate(instructions):
if idx%3 == 0:
a = (inst[0],inst[1])
elif idx%3 == 1:
b = (inst[0],inst[1])
elif idx%3 == 2:
r = (inst[0]+10000000000000,inst[1]+10000000000000)
eq1 = Eq(a[0]*x + b[0]*y,r[0])
eq2 = Eq(a[1]*x + b[1]*y,r[1])
s = solve((eq1,eq2),(x,y))
if s:
result += s[x]*a_cost
result += s[y]*b_cost
#input()
return result
start_time = time.time() start_time = time.time()
print('Part 2:',part1(), '\t\t', round((time.time() - start_time)*1000), 'ms')
start_time = time.time()
print('Part 2:',part2(), '\t\t', round((time.time() - start_time)*1000), 'ms')