Working on 2023-12-07 part2. Missing tiebreaker

2023/day7/exp

@@ -1,11 +1,23 @@
-32T3K 765
+J2566 131
-T55J5 684
+K7KK7 272
-AA8AA 21
+AA222 222
-KK677 28
+222AA 123
-AAAAA 123
+44T55 467
-KTJJT 220
+4K339 546
-23332 1
+42TT2 174
-A23A4 64
+TQTTT 710
-QQQJA 483
+84766 682
-23456 64
+K22KK 607
-HNJIP 317
+77595 922
+26778 768
+JJ667 198
+JJ2JJ 123
+44Q9A 821
+T6682 851
+3A232 890
+5Q5J4 691
+79789 305
+KK666 138
+TT9TT 742
+Q4276 489
+6T48J 921

2023/day7/exp2

@@ -0,0 +1,9 @@
+2J345 213
+22345 425
+2JJ34 654
+22234 234
+2JJJ3 623
+22223 658
+J2JJJ 987
+2JJJJ 456
+22222 604

2023/day7/part2.py

@@ -0,0 +1,201 @@
+#!/bin/python3
+
+import re
+import sys
+from pprint import pprint 
+from collections import Counter
+
+input_f  = sys.argv[1]
+
+d =[]
+rank = 0
+#prev 250197359
+strength = 'AKQT98765432J'
+print(strength)
+
+with open(input_f) as file:
+    for line in file:
+        d.append(line.split())
+pprint(d)
+print()
+
+def same_kind(x):
+    s = Counter(x)
+    for i in s.values():
+        if i == 4:
+            return True
+    return False
+
+def five_of_kind(x):
+    if len(Counter(x)) == 1:
+            return True
+    return False
+
+def full_house(x):
+    #print('full_house')
+    s = Counter(x)
+    if len(s) != 2:
+        return False
+    else:
+        tmp = list(s.values())
+        if (tmp[0] == 2 or tmp[0] == 3) and (tmp[1] == 2 or tmp[1] == 3):
+            return True
+        else:
+            return False
+
+def three_of_kind(x):
+    s = Counter(x)
+    for i in s.values():
+        if i == 3:
+            return True
+    return False
+
+def pairs(x):
+    s = Counter(x)
+    pairs = 0
+    for i in s.values():
+        if i == 2:
+            pairs += 1
+    return pairs
+
+def c_pairs(x):
+    pairs = 0
+    for i in x.values():
+        if i == 2:
+            pairs += 1
+    return pairs
+
+for idx,i in enumerate(d):
+    d[idx].append(rank)
+    card = d[idx][0]
+    tmp = Counter(card)
+    if card.find('J') != -1:
+        print(Counter(card))
+        c = list(Counter(card))
+        l = list(Counter(card).keys())
+        if list(tmp.most_common()[0])[0] == 'J' and list(tmp.most_common()[0])[1] == 5:
+            print(tmp)
+            continue
+        v = tmp['J'] 
+        del tmp['J']
+        h = list(tmp.most_common()[0])[0]
+        for j in range(0,v):
+            tmp.update(h)
+        print(tmp)
+        print()
+        if len(Counter(tmp)) == 1:
+            d[idx][2] = 7
+            continue
+        if list(Counter(tmp).most_common()[0])[1] == 4:
+            d[idx][2] = 6
+            continue
+        if list(Counter(tmp).most_common()[0])[1] == 3 and list(Counter(tmp).most_common()[1])[1] == 2:
+            d[idx][2] = 5
+            continue
+        if list(Counter(tmp).most_common()[0])[1] == 3:
+            d[idx][2] = 4
+            continue
+        if c_pairs(Counter(tmp)) == 2:
+            d[idx][2] = 3
+            continue
+        if c_pairs(Counter(tmp)) == 1:
+            d[idx][2] = 2
+            continue
+        if c_pairs(Counter(tmp)) == 0:
+            d[idx][2] = 1
+            continue
+    else: 
+        # Five of a kind, where all five cards have the same label: AAAAA
+        if five_of_kind(d[idx][0]) == True:
+            d[idx][2] = 7
+            continue
+
+        #Four of a kind, where four cards have the same label and one card has a different label: AA8AA
+        if same_kind(d[idx][0]) == True:
+            d[idx][2] = 6
+            continue
+
+        #Full house, where three cards have the same label, and the remaining two cards share a different label: 23332
+        if full_house(d[idx][0]) == True:
+            d[idx][2] = 5
+            continue
+
+        #Three of a kind, where three cards have the same label, and the remaining two cards are each different from any other card in the hand: TTT98
+        if three_of_kind(d[idx][0]) == True:
+            d[idx][2] = 4
+            continue
+
+        #Two pair, where two cards share one label, two other cards share a second label, and the remaining card has a third label: 23432
+        if pairs(d[idx][0]) == 2:
+            d[idx][2] = 3
+            continue
+
+        #One pair, where two cards share one label, and the other three cards have a different label from the pair and each other: A23A4
+        if pairs(d[idx][0]) == 1:
+            d[idx][2] = 2
+            continue
+
+        #High card, where all cards' labels are distinct: 23456
+        if pairs(d[idx][0]) == 0:
+            d[idx][2] = 1
+            continue
+#d.sort()
+
+#d = sorted(d, key=lambda x: x[2])
+
+def pp(x):
+    for p in x:
+        for q in p:
+            print(q,end='\t')
+        print()
+
+x_1 = []
+x_2 = []
+x_3 = []
+x_4 = []
+x_5 = []
+x_6 = []
+x_7 = []
+
+for y in d:
+    if y[2] == 1:
+        x_1.append(y+[[strength.index(c) for c in y[0]]])
+    if y[2] == 2:
+        x_2.append(y+[[strength.index(c) for c in y[0]]])
+    if y[2] == 3:
+        x_3.append(y+[[strength.index(c) for c in y[0]]])
+    if y[2] == 4:
+        x_4.append(y+[[strength.index(c) for c in y[0]]])
+    if y[2] == 5:
+        x_5.append(y+[[strength.index(c) for c in y[0]]])
+    if y[2] == 6:
+        x_6.append(y+[[strength.index(c) for c in y[0]]])
+    if y[2] == 7:
+        x_7.append(y+[[strength.index(c) for c in y[0]]])
+
+
+x_1 = sorted(x_1, key=lambda x: x[3],reverse=True)
+x_2 = sorted(x_2, key=lambda x: x[3],reverse=True)
+x_3 = sorted(x_3, key=lambda x: x[3],reverse=True)
+x_4 = sorted(x_4, key=lambda x: x[3],reverse=True)
+x_5 = sorted(x_5, key=lambda x: x[3],reverse=True)
+x_6 = sorted(x_6, key=lambda x: x[3],reverse=True)
+x_7 = sorted(x_7, key=lambda x: x[3],reverse=True)
+
+e = []
+
+X = [x_1,x_2,x_3,x_4,x_5,x_6,x_7]
+
+for n in X:
+    for m in n:
+        e.append(m)
+
+pprint(e)
+
+result = 0
+
+for idx,i in enumerate(e):
+    x = i[1]
+    result += (int(x) * (idx+1))
+
+print(result)